In the chemical equation $H_{2} + C l_{2} \to 2 H C I$ $H_2 + Cl_2 ->2HCI$ , what are the mole ratios?

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In the chemical equation $H_{2} + C l_{2} \to 2 H C I$ $H_2 + Cl_2 ->2HCI$ , what are the mole ratios?

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Answer 1 · 2017-09-20T18:59:59

Clearly the mole ratios of the reactants are $1:1$ $"1:1"$ , and $2 equiv$ $"2 equiv"$ of product result.

Explanation:

And this can be seen from the stoichiometric equation you have already written.....alternatively we could write....

$\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g)$ $1/2H_2(g) + 1/2Cl_2(g) rarr HCl(g)$

....which preserves the same molar ratio, i.e. the SAME STOICHOMETRY. And thus we could say that 1 equiv of dihydrogen reacts with 1 equiv of dichlorine (and note that all of the reactive elemental gases are binuclear!) to gives the 2 equiv of hydrogen chloride gas.....

And likewise we could say that $1 \cdot g$ $1*g$ of dihydrogen combines with $35 \cdot g$ $35*g$ of dichlorine to give $36 \cdot g$ $36*g$ of hydrogen chloride gas. Stoichiometry is maintained: $garbage in equal garbage out$ $"garbage in equal garbage out"$ .

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In the chemical equation $H_{2} + C l_{2} \to 2 H C I$ $H_2 + Cl_2 ->2HCI$ , what are the mole ratios?

1 Answer

Explanation:

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Science

Math

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In the chemical equation H2+Cl2→2HCI H_2 + Cl_2 ->2HCI , what are the mole ratios?

1 Answer

Explanation:

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In the chemical equation $H_{2} + C l_{2} \to 2 H C I$ $H_2 + Cl_2 ->2HCI$ , what are the mole ratios?