In the following reaction, 2NaN₃ decomposes to form 2Na plus 3N2. If 500 g of NaN3 decomposes to form 323.20 g of N2, how much Na is produced?
1 Answer
May 22, 2014
The reaction produces 176.85 g of Na.
The balanced equation is
2NaN₃ → 2Na + 3N₂
You can use either the mass of NaN₃ or of N₂ to calculate the mass of Na.
Using Mass of NaN₃
You must make the following conversions:
mass of NaN₃ → moles of NaN₃ → moles of Na → mass of Na
500 g NaN₃ ×
7.69 mol NaN₃ ×
7.69 mol Na ×
Using Mass of N₂
You must make the following conversions:
mass of N₂ → moles of N₂ → moles of Na → mass of Na
323.20 g Na ×
11.539 mol N₂ ×
7.692 mol Na ×