In the followings ,decreasing order of 1st ionisation energy will be ,i)Xe,ii)Al,iii)Be,iv)As. ?
1 Answer
Got a Periodic Table handy?
Explanation:
.......of course you have one nearby because you are doing your chemistry homework.
Now ionization energies are defined by the following rxn:
Now we know the ionization energies INCREASE across a Period from left to right as we face the Table, but DECREASE down a Group, a column of the Periodic Table.
And simple ideas of electrostatics can rationalize this trend. Incomplete electronic shells shield the nuclear charge very imperfectly. And across the Period, ionization energies should increase. This also manifests in the well known decrease in atomic radii from left to right as we face the Table. As a valence shell is completed, shielding of the nuclear charge becomes more effective, and the electrons occupy a new valence shell to begin the process again.
So we have (i) 5th Period xenon, an inert gas; (ii) 3rd Period aluminum; (iii) 2nd Period beryllium; and 4th Period arsenic. Because we compare (i) different valence shells, and (ii) different electronic configurations, it is BY NO MEANS straightforward to predict the relative order of ionization energies.
At a push we might predict the following order of DECREASING ionization energies: