In the polyatomic ion, CrO4 -2, what is the charge on the chromium atom?

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In the polyatomic ion, CrO4 -2, what is the charge on the chromium atom?

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Answer 1 · 2015-11-12T16:57:19

The oxidation state of $C r$ $Cr$ in chromate ion, $C r O_{4}^{2 -}$ $CrO_4^(2-)$ , is $V I^{+}$ $VI^+$ .

Explanation:

As far as anyone knows, the charge in chromate is localized on the oxygen (i.e ${(O =)}_{2} C r {(- O^{-})}_{2}^{-}$ $(O=)_2Cr(-O^-)_2$ ). Chromic acid, $H_{2} C r O_{4}$ $H_2CrO_4$ (or ${(O =)}_{2} C r {(- O H)}_{2}$ $(O=)_2Cr(-OH)_2$ ), is the precursor; this is a potent oxidant. In each case, the metal oxidation state ( $V I^{+}$ $VI^+$ ) is clear. Note that in this formal representation, the charge on chromium is neutral. The negative charge is borne by the 2 singly bound oxygen atoms.

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In the polyatomic ion, CrO4 -2, what is the charge on the chromium atom?

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