In the reaction $4NH_3+6NO->5N_2+6H_2O$ , how many grams of ammonia will react with 27.8 grams of nitric oxide?

Question

The molar mass of ammonia is 17.0337 grams and that of nitric oxide is 30.01 grams.

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Answer 1 · 2016-08-11T15:30:48

$"Approx. 10g ammonia will be consumed."$

How many moles of nitric oxide reacted?

$n_"NO"$ $=$ $(27.8*g)/(30.01*g*mol^-1)$ $=$ $0.927*mol$ .

Your stoichiometric equation CLEARLY shows that each equiv $NO$ requires $2/3" equiv"$ $"ammonia"$ for the comproportionation to occur.

Thus $2/3xx0.927*molxx17.0337*g*mol^-1$ $=$ $??g$