In the reaction $H_{2} (g) + F_{2} (g) \to 2 H F (g)$ $H_2(g) + F_2(g) ->2HF(g)$ , how many grams of $H F$ $HF$ gas are produced as 5 mol of fluorine react with excess $H_{2}$ $H_2$ ?

Question

8355 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-16T13:40:02

100

Normally 1 mole of $F_{2}$ $F_2$ reacts with 1 mole of $H_{2}$ $H_2$ giving 2 moles of HF (which is 20g).

We can say that 1 mole of $F_{2}$ $F_2$ gives 20 g of $H F$ $HF$ .
The questions is: 5 moles of $F_{2}$ $F_2$ give x (how much $H F$ $HF$ ?)

$1 - 20$ $1 - 20$
$5 - x$ $5 - x$
$x = 100 g$ $x = 100 g$

In the reaction H2(g)+F2(g)→2HF(g)H_2(g) + F_2(g) ->2HF(g), how many grams of HFHF gas are produced as 5 mol of fluorine react with excess H2H_2?