In the reaction represented by the equation $2 A l_{2} O_{3} \to 4 A l + 3 O_{2}$ $2Al_2O_3 -> 4Al + 3O_2$ , what is the mole ratio of aluminum to oxygen?

Question

In the reaction represented by the equation $2 A l_{2} O_{3} \to 4 A l + 3 O_{2}$ $2Al_2O_3 -> 4Al + 3O_2$ , what is the mole ratio of aluminum to oxygen?

1 Answer

Impact of this question

33129 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-17T05:41:46

$4 : 3$ $4:3$

Explanation:

As per the equation , $2$ $2$ moles of Aluminum Oxide ( $A l_{2} O_{3}$ $Al_2O_3$ ) produces $4$ $4$ moles of Aluminum ( $A l$ $Al$ ) and $3$ $3$ moles of Oxygen ( $O_{2}$ $O_2$ ).

The ratio of $A l$ $Al$ to $O$ $O$ is $\frac{4 moles}{3 moles}$ $(4 " moles")/(3 " moles")$ = $\frac{4}{3}$ $4/3$

Science

Math

Humanities

... and beyond

In the reaction represented by the equation $2 A l_{2} O_{3} \to 4 A l + 3 O_{2}$ $2Al_2O_3 -> 4Al + 3O_2$ , what is the mole ratio of aluminum to oxygen?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

In the reaction represented by the equation 2Al2O3→4Al+3O22Al_2O_3 -> 4Al + 3O_2, what is the mole ratio of aluminum to oxygen?

1 Answer

Explanation:

Related questions

Impact of this question

In the reaction represented by the equation $2 A l_{2} O_{3} \to 4 A l + 3 O_{2}$ $2Al_2O_3 -> 4Al + 3O_2$ , what is the mole ratio of aluminum to oxygen?