In triangle ABC, sin A=1/3, sin B=1/5, and b=6, how do you find side a?
1 Answer
Apr 25, 2015
Use the trig identity: a/sin A = b/sin B
a = b.(sin A/sin B) = 6. (5/3) = 10.
Use the trig identity: a/sin A = b/sin B
a = b.(sin A/sin B) = 6. (5/3) = 10.