Initially a gas is at a pressure of 12 atm, a volume of 23 L, and a temperature of 200 K, and then the pressure is raised to 14 atm and the temperature to 300 K. What is the new volume of the gas?

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Answer 1 · 2016-08-23T20:00:53

#(P_1V_1)/T_1=(P_2V_2)/T_2#

#V_2~=30L#

#V_2# #=# #(P_1V_1T_2)/(P_2T_1)#

#(12*atmxx23*Lxx300K)/(14*atmxx200*K)# #=# #??L#

The volume has increased reasonably in that the temperature has increased substantially, yet the pressure has only increased marginally.