Initially a gas is at a pressure of 12 atm, a volume of 23 L, and a temperature of 200 K, and then the pressure is raised to 14 atm and the temperature to 300 K. What is the new volume of the gas?

Question

4374 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-23T20:00:53

#(P_1V_1)/T_1=(P_2V_2)/T_2#

#V_2~=30L#

#V_2# #=# #(P_1V_1T_2)/(P_2T_1)#

#(12*atmxx23*Lxx300K)/(14*atmxx200*K)# #=# #??L#

The volume has increased reasonably in that the temperature has increased substantially, yet the pressure has only increased marginally.