Is B(OH)3 a lewis base?

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Is B(OH)3 a lewis base?

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Answer 1 · 2015-11-10T20:56:17

$B {(OH)}_{3}$ $"B"("OH")_3$ has a trigonal planar structure:

And there are no lone pairs of electrons in the boron's central $2 p_{z}$ $2p_z$ orbital. It is an empty unhybridized orbital, like this (except with $OH$ $"OH"$ instead of $H$ $"H"$ ):

Therefore, in order to bond, boron acts as an electron acceptor and takes electrons into its empty orbital, following the definition of a lewis acid.

(Afterwards, it experiences a conformational change and becomes a tetrahedral structure.)

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Is B(OH)3 a lewis base?

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