Is #f(x)=-4x^3+x^2+2x+2# increasing or decreasing at #x=2#?
1 Answer
Mar 5, 2016
decreasing at x = 2
Explanation:
To test if a function is increasing / decreasing at x = a , require to find the value of f'(a).
• If f'(a) > 0 then f(x) is increasing at x = a
• If f'(a) < 0 then f)x) is decreasing at x = a
so f(x) =
#- 4x^3 + x^2 + 2x + 2# hence: f'(x)
#= - 12x^2 + 2x + 2# and
# f'(2) = -12(2)^2 +2(2) + 2 = - 42# since f'(2) < 0 then f(x) is decreasing at x = 2
Here is the graph of f(x)
graph{-4x^3+x^2+2x+2 [-10, 10, -5, 5]}