Question

Is `f(x)=-e^(x^2-3x+2)` increasing or decreasing at `x=0`?

Answer 1

will be an increasing function

Explanation:

f'(x) will be equal to `-e^(x^2-3x+2)*(2x-3)` at zero the function is equal to 3 `e^2` so its an increasing function at zero