Question

Is the equation `V(T)=100(1.08)^T` an exponential growth or decay?

Answer 1

It is an exponential growth:
Check the BASE of your exponential; `1.08` is bigger than `1` so for increasing `T` it gets bigger.
Try for example:
`T=0 -> 1.08^T=1.08^0=1`
`T=1 -> 1.08^T=1.08^1=1.08` so the value of your function is increasing.

hope it helps!