Is the function f(x)= -4x^2 + 4xf(x)=4x2+4x even, odd or neither?

1 Answer
Oct 18, 2015

Neither

Explanation:

The quick way to spot whether a polynomial function in xx is odd or even is the powers of xx that occur. If they are all odd then the polynomial is odd. If they are all even then the polynomial is even. Note that a constant is an even power of xx - namely x^0x0.

By definition:

f(x)f(x) is odd if f(-x) = -f(x)f(x)=f(x) for all xx in the domain.

f(x)f(x) is even if f(-x) = f(x)f(x)=f(x) for all xx in the domain.

In our case, we find:

f(-1) = -4-4 = -8f(1)=44=8

f(1) = -4+4 = 0f(1)=4+4=0

So neither condition holds.

Given any function f(x)f(x), it can be expressed uniquely as the sum of an even function and an odd function, defined as follows:

f_e(x) = (f(x) + f(-x))/2fe(x)=f(x)+f(x)2

f_o(x) = (f(x) - f(-x))/2fo(x)=f(x)f(x)2

In our case we find f_e(x) = -4x^2fe(x)=4x2 and f_o(x) = 4xfo(x)=4x