Is there a easier more efficient approach for the human brain to perform elementary mathematical computations (+-×÷) that differs from what is traditionally taught in school?

1 Answer
Feb 29, 2016

It depends...

Explanation:

There are various tricks and techniques to make it easier to perform mental arithmetic, but many involve memorising more things first.

For example, (a-b)(a+b) = a^2-b^2(ab)(a+b)=a2b2. Hence if you know a few square numbers you can sometimes conveniently multiply two numbers by taking the difference of squares. For example:

17*19 = (18-1)(18+1) = 18^2-1^2 = 324 - 1 = 3231719=(181)(18+1)=18212=3241=323

So rather than memorise the whole "times table" you can memorise the 'diagonal' and use a little addition and subtraction instead.

You might use the formula:

ab = ((a+b)/2)^2 - ((a-b)/2)^2ab=(a+b2)2(ab2)2

This tends to work best if aa and bb are both odd or both even.

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For subtraction, you can use addition with 99's complement then add 11. For example, the (33 digit) 99's complement of 358358 would be 641641. So instead of subtracting 358358, you can add 641641, subtract 10001000 and add 11.

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Other methods for multiplying numbers could use powers of 22. For example, to multiply any number by 1717 double it 44 times then add the original number.

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At a more advanced level, the standard Newton Raphson method for finding the square root of a number nn is to start with an approximation a_0a0 then iterate to get better approximations using a formula like:

a_(i+1) = (a_i^2+n)/2ai+1=a2i+n2

This is all very well if you are using a four function calculator, but I prefer to work with rational approximations by separating the numerator and denominator of a_iai as p_ipi and q_iqi then iterating using:

p_(i+1) = p_i^2+n q_i^2pi+1=p2i+nq2i

q_(i+1) = 2 p_i q_iqi+1=2piqi

If the resulting numerator/denominator pair has a common factor, then divide both by that before the next iteration.

This allows me to work with integers instead of fractions. Once I think I have enough significant figures I then long divide p_i/q_ipiqi if I want a decimal approximation.