Is this equation properly balanced? $4 F e + 3 O_{2} \to 2 F e_{2} O_{3}$ $4Fe + 3O_2 -> 2 Fe_2O_3$ ?

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Is this equation properly balanced? $4 F e + 3 O_{2} \to 2 F e_{2} O_{3}$ $4Fe + 3O_2 -> 2 Fe_2O_3$ ?

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Answer 1 · 2017-05-11T02:34:50

Yes! (See explanation)

Explanation:

Count how many $F e$ $Fe$ and $O_{2}$ $O_2$ you have on both left and right sides:

You are given:

$4 F e + 3 O_{2} \to 2 F e_{2} O_{3}$ $4Fe+3O_2 -> 2Fe_2O_3$

$4 : F e : 4$ $4:Fe:4$
$6 : O_{2} : 6$ $6:O_2:6$

You actually have the same number of $F e$ $Fe$ on both sides, The same is true for $O_{2}$ $O_2$ so yes this equation is properly balanced.

For added benefit consider the following equation:

$C H_{4} + O_{2} \to C O_{2} + 2 H_{2} O$ $CH_4+O_2-> CO_2+2H_2O$

ASK: Is this equation balanced? Quick answer: No

ASK: So how do we know and how do we then balance it?

DO: Count the number of each atom type you have on each side of the equation:

$1 : C : 1$ $1:C:1$
$4 : H : 4$ $4:H:4$
$2 : O : 4$ $2:O:4$

As you can see everything is balanced except for $O$ $O$ To balance O we can simply add a coefficient of $2$ $2$ in front of $O_{2}$ $O_2$ on the left side which would result in $4$ $4$ $O$ $O$ atoms:

$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$ $CH_4+color(red)(2)O_2-> CO_2+2H_2O$

$1 : C : 1$ $1:C:1$
$4 : H : 4$ $4:H:4$
$4 : O : 4$ $4:O:4$

Everything is now balanced.

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Is this equation properly balanced? $4 F e + 3 O_{2} \to 2 F e_{2} O_{3}$ $4Fe + 3O_2 -> 2 Fe_2O_3$ ?

1 Answer

Explanation:

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Is this equation properly balanced? 4Fe+3O2→2Fe2O34Fe + 3O_2 -> 2 Fe_2O_3?

1 Answer

Explanation:

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Is this equation properly balanced? $4 F e + 3 O_{2} \to 2 F e_{2} O_{3}$ $4Fe + 3O_2 -> 2 Fe_2O_3$ ?