kindly solve this question?

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1 Answer
Jul 29, 2018

2

Explanation:

For any line:

  • {(y = mx + b), (y' = m):} qquad m,b in RR

Plugging into the DE:

m + xm^2 - y = 0

implies y = m^2 x + m qquad qquad = mx + b

m = m^2 implies m = 0,1 implies b = 0,1

:. y = {(0),(x + 1):} both satisfy the DE