Lead nitrate can be decomposed by heating. What is the percent yield of the decomposition reaction if 9.9 g of $P b {(N O_{3})}_{2}$ $Pb(NO_3)_2$ are heated to give 5.5 g of $P b O$ $PbO$ ??

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Answer 1 · 2017-05-31T04:28:09

$Percentage yield ≅ 80 %$ $"Percentage yield"~=80%$

We need (i) a stoichiometric equation........

$Pb(NO_3)_2 +Delta rarr PbO(s)+2NO_2(g)+1/2O_2(g)$

This simply must be known; nitrates undergo thermal decomposition to give oxide and nitric oxide and dioxygen gas.

And (ii). given the 1:1 stoichiometry between nitrate and oxide, we needs equivalent quantities of lead oxide and lead nitrate:

$"Percentage yield"="Moles of lead oxide"/"Moles of lead nitrate"xx100%=$

$((5.5*g)/(223.2*g*mol^-1))/((9.9*g)/(331.2*g*mol^-1))xx100%=??%$

Lead nitrate can be decomposed by heating. What is the percent yield of the decomposition reaction if 9.9 g of Pb(NO_3)_2Pb(NO3)2Pb(NO_3)_2are heated to give 5.5 g of PbOPbOPbO??