Let #5 x^2+ 3 x + xy = 3# and #y( 3 ) = -17#, how do you find y'( 3 ) by implicit differentiation?
1 Answer
Oct 6, 2015
y'= -16/3
Explanation:
Implicit differentiation of the given equation, term by term gives 10x +3+xy' +y=0.
For getting y'(3), put x=3 and for y put -17, because it is given that y(3)=-17. Accordingly,
10(3) +3 +3y' -17 =0
3y'= -16
y'= -16/3
