Let $f (x) = \frac{12}{4 x + 2}$ $f(x) = 12/(4 x + 2$ how do you find f(-1)?

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Answer 1 · 2016-07-05T22:26:03

$f (- 1) = - 6$ $f(-1) = -6$

All we have to do is plug in $- 1$ $-1$ for $x$ $x$ .

So:

$f (x) = \frac{12}{4 x + 2}$ $f(x) = 12/(4x+2)$

Plug in $- 1$ $-1$ :

$f (- 1) = \frac{12}{4 (- 1) + 2}$ $f(-1) = 12/(4(-1)+2)$

Simplify the denominator:

$f (- 1) = \frac{12}{- 2}$ $f(-1) = 12/-2$

Divide:

$f (- 1) = - 6$ $f(-1) = -6$

And that's your solution.

Let f(x)=124x+2f(x) = 12/(4 x + 2 how do you find f(-1)?