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Let $f (x) = 2 x^{2} + 2$ $f(x)=2x^2+2$ , how do you find f(0.3)?

1 Answer

Oct 27, 2016

$f (x) = y = 2.18$ $f(x) = y =2.18$

Explanation:

$f (x) = 2 x^{2} + 2 \leftarrow$ $f(color(red)(x)) = 2x^2 +2" "larr$ the right side shows what is done to $x$ $x$
$x ↓$ $color(white)(x)darr$
$f (0.3) \leftarrow$ $f(color(red)(0.3))" "larr$ you are told that $x$ $x$ has the value $0.3$ $0.3$

$f (x) = 2 x^{2} + 2$ $f(color(red)(x)) = 2color(red)(x^2) +2$

$f (0.3) = 2 ({0.3}^{2}) + 2$ $f(color(red)(0.3)) = 2color(red)((0.3^2)) +2$

$\times \times = 2 \times 0.09 + 2$ $color(white)(xxxx) =2 xx 0.09 +2$

$\times \times = 2.18$ $color(white)(xxxx) =2.18$

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