Let f(x) = 2x + 2, how do you solve $f^{- 1} (x)$ $f^-1(x)$ when x = 4?

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Answer 1 · 2017-06-25T14:37:41

One.

Exchange x and y and the inverse is $x = 2 y + 2$ $x = 2y + 2$

$x - 2 = 2 y \Rightarrow y = \frac{x}{2} - 1 = f^{- 1} (x)$ $x - 2 = 2y => y = x/2 - 1 = f^-1(x)$

$f^{- 1} (4) = \frac{4}{2} - 1$ $f^-1(4) = 4/2 - 1$

Let f(x) = 2x + 2, how do you solve f−1(x)f^-1(x) when x = 4?