Let #f(x)= 3- (x+ 4)+ 2x#. How do you find all values of x for which f(x) is at least 6?

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Answer 1 · 2016-12-12T10:45:45

#x >= 7#

Set #f(x)>=6 larr" at least 6 "=>" greater than or equal to 6"#

#3-(x+4)+2x>=6#

#3-x-4+2x>=6#

#3-4+2x-x>=6#

#-1+x>= 6#

#x >= 7#

Answer 2 · 2016-12-12T10:56:01

Solution: #x>=7#. In interval notation expressed as #[7, oo)#

#f(x)=3-(x+4)+2x >=6 or 3-x-4+2x>=6 or x -1 >= 6 or x>= 7#
Solution: #x>=7#. In interval notation expressed as #[7, oo)# [Ans]