Let f(x)=9x-8f(x)=9x8, how do you find (fof)(5)(fof)(5)?

1 Answer
Dec 6, 2016

Assuming you mean f(5)f(5), then f(5)=37f(5)=37

Explanation:

If we have f(x)f(x) as some transformation applied to xx, then f(a)f(a) will be the same transformation but applied to aa.

So if f(x)=2x^2+9f(x)=2x2+9, then f(a)=2a^2+9f(a)=2a2+9. And if we say a=5a=5, then f(a)=2(5)^2+9=59f(a)=2(5)2+9=59

So, using this principle, f(5) = 9(5)-8=37f(5)=9(5)8=37