Let $f (x) = x^{2} - 2 x + 5$ $f(x)=x^2-2x+5$ and $g (x) = \frac{4}{x - 1}$ $g(x)=4/(x-1)$ , how do you find $(f o g) (3)$ $(fog)(3)$ ?

Question

Let $f (x) = x^{2} - 2 x + 5$ $f(x)=x^2-2x+5$ and $g (x) = \frac{4}{x - 1}$ $g(x)=4/(x-1)$ , how do you find $(f o g) (3)$ $(fog)(3)$ ?

1 Answer

Impact of this question

8677 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-27T18:33:43

$5$ $5$

Explanation:

Start by finding (f￮g)(x)

To find this function, substitute $x = \frac{4}{x - 1} That is g(x) into f (x)$ $x=4/(x-1)"That is g(x) into " f(x)$

$rArr(f￮g)(x)=(4/(x-1))^2-2(4/(x-1))+5$

$=16/(x-1)^2-8/(x-1)+5$

Now substitute x = 3

$rArr(f￮g)(3)=16/(3-1)^2-8/(3-1)+5$

$=16/4-8/2+5=4-4+5=5$

Science

Math

Humanities

... and beyond

Let $f (x) = x^{2} - 2 x + 5$ $f(x)=x^2-2x+5$ and $g (x) = \frac{4}{x - 1}$ $g(x)=4/(x-1)$ , how do you find $(f o g) (3)$ $(fog)(3)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

Let f(x)=x^2-2x+5f(x)=x2−2x+5f(x)=x^2-2x+5 and g(x)=4/(x-1)g(x)=4x−1g(x)=4/(x-1), how do you find (fog)(3)(fog)(3)(fog)(3)?

1 Answer

Explanation:

Related questions

Impact of this question

Let $f (x) = x^{2} - 2 x + 5$ $f(x)=x^2-2x+5$ and $g (x) = \frac{4}{x - 1}$ $g(x)=4/(x-1)$ , how do you find $(f o g) (3)$ $(fog)(3)$ ?