Let f(x) = x - 2 and $g (x) = x^{2} - 7 x - 9$ $g(x) = x^2 - 7x - 9$ how do you find f(g(-1))?

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Answer 1 · 2016-09-03T19:45:17

f(g(-1)) = -3

The first step is to find g(-1):
$g (- 1) = {(- 1)}^{2} - 7 (- 1) - 9$ $g(-1) = (-1)^2 - 7(-1) - 9$
$= 1 + 7 - 9 = - 1$ $= 1 + 7 - 9 = -1$

Since we know g(-1) = -1, we can say f(g(-1)) = f(-1).

The next step is to do f(-1);
$f (- 1) = - 1 - 2 = - 3$ $f(-1) = -1 - 2 = -3$

Let f(x) = x - 2 and g(x)=x2−7x−9g(x) = x^2 - 7x - 9 how do you find f(g(-1))?