Let f(x) = x + 8 and $g (x) = x^{2} - 6 x - 7$ $g(x) = x^2 - 6x - 7$ how do you find f(g(2))?

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Let f(x) = x + 8 and $g (x) = x^{2} - 6 x - 7$ $g(x) = x^2 - 6x - 7$ how do you find f(g(2))?

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Answer 1 · 2017-03-31T11:53:27

See the entire solution process below:

Explanation:

First, evaluate $g (2)$ $g(2)$ by substituting $2$ $color(red)(2)$ for each occurrence of $x$ $color(red)(x)$ in the function $g (x)$ $g(x)$ :

$g (x) = x^{2} - 6 x - 7$ $g(color(red)(x)) = color(red)(x)^2 - 6color(red)(x) - 7$ becomes:

$g (2) = 2^{2} - (6 \times 2) - 7$ $g(color(red)(2)) = color(red)(2)^2 - (6 xx color(red)(2)) - 7$

$g (2) = 4 - 12 - 7$ $g(color(red)(2)) = 4 - 12 - 7$

$g (2) = - 15$ $g(color(red)(2)) = -15$

We can now substitute $g (2)$ $color(blue)(g(2))$ which is $- 15$ $color(blue)(-15)$ for each occurrence of $x$ $color(blue)(x)$ in the function $f (x)$ $f(x)$ :

$f (x) = x + 8$ $f(color(blue)(x)) = color(blue)(x) + 8$ becomes:

$f (- 15) = - 15 + 8$ $f(color(blue)(-15)) = color(blue)(-15) + 8$

$f (- 15) = - 7$ $f(color(blue)(-15)) = -7$

Therefore, $f (g (2)) = - 7$ $f(g(2)) = -7$

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Let f(x) = x + 8 and $g (x) = x^{2} - 6 x - 7$ $g(x) = x^2 - 6x - 7$ how do you find f(g(2))?

1 Answer

Explanation:

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Let f(x) = x + 8 and g(x)=x2−6x−7g(x) = x^2 - 6x - 7 how do you find f(g(2))?

1 Answer

Explanation:

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Let f(x) = x + 8 and $g (x) = x^{2} - 6 x - 7$ $g(x) = x^2 - 6x - 7$ how do you find f(g(2))?