Let R be the region enclosed by #y= e^(2x), y=0, and y=2#. What is the volume of the solid produced by revolving R around the x-axis?
1 Answer
Jan 18, 2017
Explanation:
y = 2 meets
The x-axis y = 0 is the asymptote to
Now,
volume
The graph shows the area that is revolved.
graph{(y-.1)(e^(2x)-y)(x-.5ln2+.0001y)=0 [-1.5, 1.5, 0, 2,1]}