Let z = 1-i. Find abs(z) ... How?

Question

Abs = absolute value
a. sqrt(3)
b. sqrt(2)
c. none of the above
d. 2
e. 1

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Answer 1 · 2016-09-17T09:21:56

Answer is #sqrt2# i.e. (b).

Absolute vale of a complex number #a+bi# is given by #sqrt(a^2+b^2)#.

Hence as #z=1-i#,

#abs(z)=sqrt(1^2+(-1)^2#

= #sqrt(1+1)=sqrt2#

Hence, answer is (b).