Lisa, an experienced shipping clerk, can fill a certain order in 10 hours. Tom, a new clerk, needs 13 hours to do the same job. Working together, how long will it take them to fill the order?

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Lisa, an experienced shipping clerk, can fill a certain order in 10 hours. Tom, a new clerk, needs 13 hours to do the same job. Working together, how long will it take them to fill the order?

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Answer 1 · 2016-12-28T11:59:34

Both together will fill the order in $5.65 (2 d p)$ $5.65(2dp)$ hours.

Explanation:

In $1$ $1$ hour Lisa does $\frac{1}{10}$ $1/10$ th of the order.
In $1$ $1$ hour Tom does $\frac{1}{13}$ $1/13$ th of the order.

In $1$ $1$ hour both together do $(\frac{1}{10} + \frac{1}{13}) = \frac{13 + 10}{130} = \frac{23}{130}$ $(1/10+1/13) = (13+10)/130 =23/130$ th of the order.

Both together do $\frac{23}{130}$ $23/130$ th part of the order in $1$ $1$ hour.

Therefore, both together will do full order in $\frac{1}{\frac{23}{130}} = \frac{130}{23} = 5.65 (2 d p)$ $1/(23/130) =130/23= 5.65(2dp)$ hours. [Ans]

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Lisa, an experienced shipping clerk, can fill a certain order in 10 hours. Tom, a new clerk, needs 13 hours to do the same job. Working together, how long will it take them to fill the order?

1 Answer

Explanation:

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