Mixture containing .538mol $H e$ $He$ gas, .315mol $N e$ $Ne$ gas .103 $A r$ $Ar$ gas, is confined in 7.00-L vessel at $25^{o}$ $25^o$ Celsius. How do you calculate partial pressure of each gas in mixture? How would you calculate the total pressure of the mixture?

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Mixture containing .538mol $H e$ $He$ gas, .315mol $N e$ $Ne$ gas .103 $A r$ $Ar$ gas, is confined in 7.00-L vessel at $25^{o}$ $25^o$ Celsius. How do you calculate partial pressure of each gas in mixture? How would you calculate the total pressure of the mixture?

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Answer 1 · 2017-02-23T10:07:46

$Dalton's law of partial pressures states that.........$ $"Dalton's law of partial pressures states that........."$

Explanation:

$Dalton's law of partial pressures states that in a gaseous$ $"Dalton's law of partial pressures states that in a gaseous"$
$partial pressure exerted by a component gas is the same as$ $"partial pressure exerted by a component gas is the same as"$
$the pressure it would exert if it alone occupied the container.$ $"the pressure it would exert if it alone occupied the container."$

$The total pressure is the sum of the individual partial pressures.$ $"The total pressure is the sum of the individual partial pressures."$

Here $P_{Total} = P_{He} + P_{Ne} + P_{Ar}$ $P_"Total"=P_"He"+P_"Ne"+P_"Ar"$

$= \frac{n_{He} R T}{V} + \frac{n_{Ne} R T}{V} + \frac{n_{Ar} R T}{V}$ $=(n_"He"RT)/V+(n_"Ne"RT)/V+(n_"Ar"RT)/V$

$= \frac{R T}{V} (n_{He} + n_{Ne} + n_{Ar})$ $=(RT)/V(n_"He"+n_"Ne"+n_"Ar")$

You have the molar quantities; you have the temperature, and volume; you have $R = 0.0821 \cdot L \cdot a t m \cdot K^{- 1} \cdot m o l^{- 1}$ $R=0.0821*L*atm*K^-1*mol^-1$ . Have at it.

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Mixture containing .538mol $H e$ $He$ gas, .315mol $N e$ $Ne$ gas .103 $A r$ $Ar$ gas, is confined in 7.00-L vessel at $25^{o}$ $25^o$ Celsius. How do you calculate partial pressure of each gas in mixture? How would you calculate the total pressure of the mixture?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

Mixture containing .538mol HeHe gas, .315mol NeNe gas .103 ArAr gas, is confined in 7.00-L vessel at 25o25^oCelsius. How do you calculate partial pressure of each gas in mixture? How would you calculate the total pressure of the mixture?

1 Answer

Explanation:

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Impact of this question

Mixture containing .538mol $H e$ $He$ gas, .315mol $N e$ $Ne$ gas .103 $A r$ $Ar$ gas, is confined in 7.00-L vessel at $25^{o}$ $25^o$ Celsius. How do you calculate partial pressure of each gas in mixture? How would you calculate the total pressure of the mixture?