Molarity of 4% (W/V) NaOH would be ??

1 Answer
Feb 12, 2018

Given the starting conditions....#"molarity"=1.00*mol*L^-1#

Explanation:

Given the starting conditions, we presume that a #4*g# mass of sodium hydroxide is dissolved in a #100*mL# volume of water....and such a dissolution would involve MINIMAL change to the volume....

And the given definition of #"molarity"="moles of solute (mol)"/"volume of solution (L)"#...and thus units of #mol*L^-1#.

And so we take the quotient...

#((4*g)/(40.0*g*mol^-1))/(100*mLxx10^-3*L*mL^-1)=1.00*mol*L^-1#