$N a_{3} N$ $Na_3N$ decomposes to form sodium and nitrogen gas at STP. If 13.7 L of nitrogen is produced, how many moles of $N a_{3} N$ $Na_3N$ was used (22.4 L = 1 mole of any gas) ?

Question

$N a_{3} N$ $Na_3N$ decomposes to form sodium and nitrogen gas at STP. If 13.7 L of nitrogen is produced, how many moles of $N a_{3} N$ $Na_3N$ was used (22.4 L = 1 mole of any gas) ?

1 Answer

Impact of this question

3090 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-29T16:25:35

$1.22$ $1.22$ mol $N a_{3} N$ $Na_3N$

Explanation:

Given: $N a_{3} N$ $Na_3N$ decomposes to form sodium (Na) and Nitrogen ( $N_{2})$ $N_2)$ at STP (standard temperature and pressure). At STP $22.4 L = 1$ $22.4 L = 1$ mole of gas

First you need to write a skeleton equation and then balance it. You need to realize that nitrogen is a diatomic element $N_{2}$ $N_2$ .

skeleton equation: $N a_{3} N \to N a + N_{2}$ $" "Na_3N -> Na + N_2$

balanced: $2 N a_{3} N \to 6 N a + N_{2}$ $" "2Na_3N -> 6Na + N_2$

The balanced equation gives us the mole ratio of sodium nitrate to nitrogen produced: $\frac{2}{1}$ $2/1$ .

$13.7 cancel(L N_2) xx (1 cancel(mol N_2))/(22.4 cancel(L N_2)) xx (2 mol Na_3N)/(1 cancel(mol N_2)) = 1.22" mol "Na_3N$

Science

Math

Humanities

... and beyond

$N a_{3} N$ $Na_3N$ decomposes to form sodium and nitrogen gas at STP. If 13.7 L of nitrogen is produced, how many moles of $N a_{3} N$ $Na_3N$ was used (22.4 L = 1 mole of any gas) ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

Na_3NNa3NNa_3N decomposes to form sodium and nitrogen gas at STP. If 13.7 L of nitrogen is produced, how many moles of Na_3NNa3NNa_3N was used (22.4 L = 1 mole of any gas) ?

1 Answer

Explanation:

Related questions

Impact of this question

$N a_{3} N$ $Na_3N$ decomposes to form sodium and nitrogen gas at STP. If 13.7 L of nitrogen is produced, how many moles of $N a_{3} N$ $Na_3N$ was used (22.4 L = 1 mole of any gas) ?