Objects A and B are at the origin. If object A moves to (3 ,6 )(3,6) and object B moves to (1 ,-4 )(1,4) over 1 s1s, what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.

1 Answer
Sep 28, 2017

The relative velocity is == <-2, -10> ms^-1==<2,10>ms1

Explanation:

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The absolute velocity of AA is v_A=1/1<3,6> = <3,6> ms^-1vA=11<3,6>=<3,6>ms1

The absolute velocity of BB is v_B=1/1<1,-4> = <1,-4> ms^-1vB=11<1,4>=<1,4>ms1

The relative velocity of BB with respect to AA is

v_(B//A) =v_B-v_A= <1,-4> - <3,6>vB/A=vBvA=<1,4><3,6>

= <(1-3), (-4-6)> =<(13),(46)>

= <-2, -10> ms^-1=<2,10>ms1