Objects A and B are at the origin. If object A moves to (-6 ,-2 )(6,2) and object B moves to (-5 ,-4 )(5,4) over 3 s3s, what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.

1 Answer
Jul 7, 2016

v_"AB"=sqrt5/3 " "m/svAB=53 ms
"please look over the animation"please look over the animation

Explanation:

enter image source here

vec a:"represents velocity of B from perspective of A"a:represents velocity of B from perspective of A
u:"(red vector) represents velocity of A"u:(red vector) represents velocity of A
v=u:"represents velocity of B"v=u:represents velocity of B

"note that "vec a=vec w-vec unote that a=wu

enter image source here

"you need to find the relative displacement"you need to find the relative displacement
"let "Delta x" be relative displacement"
"please look over the figure above"

Delta x=sqrt(AG^2+GB^2)

"or:"

A=(-6,-2)" ; "B=(-5,-4)
Delta x=sqrt((-5+6)^2+(-4+2)^2)

Delta x=sqrt(1^2+(-2)^2)=sqrt(1+4)=sqrt5

Delta t=3" "s

v_"AB"=(Delta x)/(Delta t)

v_"AB"=sqrt5/3 " "m/s