Objects A and B are at the origin. If object A moves to $(- 6, - 2)$ $(-6 ,-2 )$ and object B moves to $(5, 4)$ $(5 ,4 )$ over $3 s$ $3 s$ , what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.

Question

1620 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-22T08:24:29

The relative velocity is $= < \frac{11}{3}, 2 > m s^{- 1}$ $= <11/3, 2> ms^-1$

![www.slideshare.net]( useruploads.socratic.org )

The absolute velocity of $A$ $A$ is $v_{A} = \frac{1}{3} < - 6, - 2 > = < - 2, - \frac{2}{3} > m s^{- 1}$ $v_A=1/3 <-6,-2> = <-2,- 2/3> ms^-1$

The absolute velocity of $B$ $B$ is $v_{B} = \frac{1}{3} < 5, 4 > = < \frac{5}{3}, \frac{4}{3} > m s^{- 1}$ $v_B=1/3 <5,4> = <5/3, 4/3> ms^-1$

The relative velocity of $B$ $B$ with respect to $A$ $A$ is

$v_{B / A} = v_{B} - v_{A}$ $v_(B//A)=v_B-v_A$

$= < \frac{5}{3}, \frac{4}{3} > - < - 2, - \frac{2}{3} >$ $=<5/3, 4/3> - <-2, -2/3>$

$= < \frac{5}{3} + 2, \frac{4}{3} + \frac{2}{3} >$ $= <5/3+2, 4/3 +2/3>$

$= < \frac{11}{3}, 2 > m s^{- 1}$ $= <11/3, 2> ms^-1$

Objects A and B are at the origin. If object A moves to (−6,−2)(-6 ,-2 ) and object B moves to (5,4)(5 ,4 ) over 3s3 s, what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.