Objects A and B are at the origin. If object A moves to $(- 8, 7)$ $(-8 ,7 )$ and object B moves to $(6, - 2)$ $(6 ,-2 )$ over $1 s$ $1 s$ , what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.

Question

1505 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-23T09:54:49

The relative velocity is $= 14 \to i - 9 \to j$ $=14veci-9vecj$

enter image source here

The absolute velocity of $A$ $A$ is

${\to v}_{A} = \frac{1}{<} - 8, 7 \geq < - 8, 7 >$ $vecv_A=1/<-8,7>=<-8,7>$

The absolute velocity of $B$ $B$ is

${\to v}_{B} = \frac{1}{1} < 6, - 2 > = < 6, - 2 >$ $vecv_B=1/1<6,-2> = <6,-2>$

The relative velocity of $B$ $B$ with respect to $A$ $A$ is

${\to v}_{B / A} = {\to v}_{B} - {\to v}_{A}$ $vecv_(B//A)=vecv_B-vecv_A$

$= < 6, - 2 > - < - 8, 7 >$ $= <6,-2 > - <-8,7>$

$= < 14, - 9 > m s^{- 1}$ $=<14,-9> ms^-1$

Objects A and B are at the origin. If object A moves to (−8,7)(-8 ,7 ) and object B moves to (6,−2)(6 ,-2 ) over 1s1 s, what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.