Question

On a typical summer evening the temperature was 90°F at 7:00 PM. At 8:00 A.M. the next morning the temperature was 70.5 F. What is the average rate of change in temperature?

Answer 1

`1.5 (""^oF)/(hr)`

Explanation:

I wouldn't necessarily call this a chemistry-related question, but it doesn't matter, I'll help.

The average rate of change of temperature with respect to time in this case can be represented by the equation

`(DeltaT^o)_(av) = (DeltaT^o)/(Deltat)`

where

`(DeltaT^o)_(av)` is the average rate of change of temperature with time,

`DeltaT^o` is the total change in temperature over the time period

and `Deltat` is the total change in time

The total change in temperature over the time period is

`90 ^oF - 70.5 ^oF = **19.5 ^oF**`

and the total time change is

`20:00` (for convenience) `- 7:00 = **13hr**`

Plugging values into the equation, we have

`(DeltaT^o)_(av) = (DeltaT^o)/(Deltat) = (19.5 ^oF)/(13hr) = 1.5 (""^oF)/(hr)`