On the figure given show that #bar(OC)# is #sqrt(2)#?
1 Answer
Sep 14, 2016
WOW...I finally got it...although it seems too easy...and probably it is not the way you wanted it!
Explanation:
I considered the two small circles as equal and having radius
According to this, the distance
Now, I applied Pythagoras to the triangle
or:
so:
Does it make sense...?