One canned juice drink is 20% orange juice; another is 10% orange juice. How many liters of each should be mixed together in order to get 10L that is 16% orange juice?

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Answer 1 · 2018-07-24T15:05:20

The volume of $10 %$ $10%$ is $= 6 L$ $=6L$ and the volume of $10 %$ $10%$ is $= 4 L$ $=4L$

Perform a material balance wrt orange juice

The total volume is $= 10 L$ $=10L$

Let the volume of $20 %$ $20%$ orange juice be $= v L$ $=vL$

Then,

The volume of $10 %$ $10%$ orange juice is $= (10 - v) L$ $=(10-v)L$

The final percentage is $= 16 %$ $=16%$ orange juice

Therefore,

$\frac{20}{100} \cdot v + \frac{10}{100} \cdot (10 - v) = 10 \cdot \frac{16}{100}$ $20/100*v+10/100*(10-v)=10*16/100$

$20 v + 100 - 10 v = 160$ $20v+100-10v=160$

$10 v = 60$ $10v=60$

$v = 6 L$ $v=6L$