Question

Part of the proceeds from a garage sale was $490 worth of $10 and $20 bills. lf there were 4 more $10 bills than $20 bills, how do you find the number of each denomination?

Answer 1

15 ($20 dollar bills) and 19 ($10 dollar bills).

Explanation:

If we let `x` be the number of $20 dollar bills then there are `x+4` $10 dollar bills.

The equation of the problem is:
`10(x+4)+20(x)=490`
`10x+40+20x=490`
`30x=450`
`x=15`

Then there are 15 $20 dollar bills and 19 $10 dollar bills.

Answer 2

19 `$10` bills and 15 `$20` bills

Explanation:

Your equation:
`20*x + 10*(4+x)=490`

`20x+40+10x=490`

`30x=450`

`x=15`

(x indicates number of #$20 bills).

Since there are 4 more bills under `$10` category compared to the other, Your 10 dollar bills number is `=15+4=19`.