Physics :- Motion in a straight line ....... HELP?

Question

the distance traveled by a particle along a straight line is given by
s= #180 t+50 t ^2# find
the initial velocity of the particle
velocity at the end of 4 second
acceleration of the particle.

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Answer 1 · 2018-06-23T14:32:27

I tried this:

I would try deriving your expression to find the velocity and again to find the acceleration.

So we get:

#(ds)/(dt)=v(t)=180+100t#...........................................(1)

Initial velocity at #t=0#

#v(0)=180m/s#

At #t=4#:

#v(4)=180+400=580m/s#

For the acceleration (derive (1)):

#(d(t))/(dt)=a(t)=100m/s^2#