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Answer 1 · 2018-04-24T13:48:12

$37$ $37$

Explanation:

Well, if $B$ $B$ is the centre of the circle, then it will intersect chord $A C$ $AC$ at the midpoint of it, which is $D$ $D$ , and $B D$ $BD$ becomes the perpendicular bisector of $A C$ $AC$ .

So, we have get $∠ A D B = 90^{\circ}$ $/_ADB=90^@$ .

Looking at $DeltaADB, /_ADB=90^@,/_DAB=53^@$ .

Therefore, the measure of $/_ABD$ will be:

$/_ABD=180^@-/_ADB-/_DAB$

$=180^@-90^@-53^@$

$=90^@-53^@$

$=37^@$

Since you want the answer without the units, we can leave out the degrees sign, and the numeric answer will be $mathbb(37)$ .

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