Please solve q 102?

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Answer 1 · 2018-03-11T15:57:29

Let,after the collision along the initial pathway of the ball,the wedge will move with velocity $v$ ,

$m*sqrt(2) = m*0 +2mv$ (as after the collision the ball will have no component along its initial diection of motion)

So, $v=1/sqrt(2)$

Now,applying law of conservation of energy,as frictional force is neglected,

$1/2 m (sqrt2)^2 = 1/2 m x^2 +1/2 (2m) (1/sqrt(2))^2$ (let,velocity of the ball after the impact is $x$ )

So,we get, $2=x^2 +1$

or, $x^2=1$

or, $x=1 ms^-1$