Please solve q 11?

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Answer 1 · 2018-04-01T17:54:08

The answer is $= 1$ $=1$

If $x + y = 2 z$ $x+y=2z$

Then,

$x = 2 z - y$ $x=2z-y$

Therefore,

$\frac{x}{x - z} = \frac{2 z - y}{2 z - y - z} = \frac{2 z - y}{z - y}$ $x/(x-z)=(2z-y)/(2z-y-z)=(2z-y)/(z-y)$

So,

$\frac{x}{x - z} + \frac{z}{y - z} = \frac{2 z - y}{z - y} + \frac{z}{y - z}$ $x/(x-z)+z/(y-z)=(2z-y)/(z-y)+z/(y-z)$

$= \frac{2 z - y}{z - y} - \frac{z}{z - y}$ $=(2z-y)/(z-y)-z/(z-y)$

$= \frac{2 z - y - z}{z - y}$ $=(2z-y-z)/(z-y)$

$= \frac{z - y}{z - y}$ $=(z-y)/(z-y)$

$= 1$ $=1$