Please solve q 132?

Question

1060 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-04T18:05:09

The answer is $option (2)$ $"option (2)"$

Apply the following equation (derived from Bernouilli's Equation)

$p_{x} - p_{y} = \frac{ρ}{2} (v_{y}^{2} - v_{x}^{2})$ $p_x-p_y=rho/2(v_y^2-v_x^2)$

$Deltap=rho/2(v_y^2-v_x^2)$

The density of water is $rho=1000kgm^-3$

The difference in pressure is

$Deltap=rhogh=1000*10*0.0051=51Pa$

The speed at $x$ is $v_x=0.02ms^-1$

Therefore,

$v_y^2-v_x^2=51*2/1000=0.102$

So,

$v_y^2=0.102+0.02^2=0.1024$

$v_y=sqrt(0.1024)=0.32ms^-1$

The speed at $y$ is $=32cms^-1$

The answer is $"option (2)"$