Please solve q 14?

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Answer 1 · 2018-04-01T18:09:53

The answer is $option (c)$ $"option (c)"$

If $a + b = 2 c$ $a+b=2c$

Then,

$a = 2 c - b$ $a=2c-b$

And

$\frac{a}{a - c} = \frac{2 c - b}{2 c - b - c} = \frac{2 c - b}{c - b}$ $a/(a-c)=(2c-b)/(2c-b-c)=(2c-b)/(c-b)$

Therefore,

$\frac{a}{a - c} + \frac{c}{b - c} = \frac{2 c - b}{c - b} + \frac{c}{b - c}$ $a/(a-c)+c/(b-c)=(2c-b)/(c-b)+c/(b-c)$

$= \frac{2 c - b}{c - b} - \frac{c}{c - b}$ $=(2c-b)/(c-b)-c/(c-b)$

$= \frac{2 c - b - c}{c - b}$ $=(2c-b-c)/(c-b)$

$= \frac{c - b}{c - b}$ $=(c-b)/(c-b)$

$= 1$ $=1$

The answer is $option (c)$ $"option (c)"$