Please solve q 32?

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Answer 1 · 2018-04-12T12:15:45

The answer is $option (d)$ $"option (d)"$

Let

$\frac{a}{b + c - 1} = k$ $a/(b+c-1)=k$

$\frac{b}{c + a - b} = k$ $b/(c+a-b)=k$

$\frac{c}{a + b - c} = k$ $c/(a+b-c)=k$

Then,

$a = k (b + c - 1)$ $a=k(b+c-1)$

$b = k (c + a - b)$ $b=k(c+a-b)$

$c = k (a + b - c)$ $c=k(a+b-c)$

Adding the equations

$a+b+c=cancelkb+cancelkc-k+kc+ka-cancelkb+ka+kb-cancelkc$

$=ka+kb+kc-k$

$k=(a+b+c)/(a+b+c-1)$

The answer is $"option (d)"$