Please solve q 40?

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Please solve q 40?

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Answer 1 · 2018-02-19T09:13:23

$(2) 2^{\frac{1}{4}} (\sqrt{2} + \sqrt{3})$ $(2)" " 2^(1/4) (sqrt(2)+sqrt(3))$

Explanation:

$x^{2} = \sqrt{48} + \sqrt{50}$ $x^2 = sqrt(48) + sqrt(50)$
$\Rightarrow x^{2} = 4 \sqrt{3} + 5 \sqrt{2}$ $=> x^2 = 4 sqrt(3) + 5 sqrt(2)$
$\Rightarrow x^{2} = \frac{4 \sqrt{6} + 10}{\sqrt{2}}$ $=> x^2 = (4 sqrt(6) + 10)/sqrt(2)$
$\Rightarrow x^{2} = \frac{{(2 + \sqrt{6})}^{2}}{\sqrt{2}}$ $=> x^2 = (2 + sqrt(6))^2/sqrt(2)$
$\Rightarrow x = \frac{2 + \sqrt{6}}{2^{\frac{1}{4}}}$ $=> x = (2 + sqrt(6))/2^(1/4)$
$\Rightarrow x = 2^{\frac{1}{4}} (\sqrt{2} + \sqrt{3})$ $=> x = 2^(1/4) (sqrt(2) + sqrt(3))$

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Please solve q 40?

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