Question

Please solve q 51?

Answer 1

The answer is `"option (2)"`

Explanation:

The force exerted on the water by the hose is

`F_1=(Deltap_(w1))/(Deltat)=(m_1v_1)/(Deltat)`

and

`F_2=(Deltap_(w2))/(Deltat)=(m_2v_2)/(Deltat)=(2m_1*2v_1)/(Deltat)`

`=4((m_1v_1)/(Deltat))`

`=4F_1`

According to Newton's third Law, the water exerts an equal force back on the hose. Thus, the fireman must apply a force in the direction of the water stream to hold the hose stationary.

The answer is `"option (2)"`